Paul and Dylan had the same number of cards at first. After Paul had bought another 39 cards and Dylan had lost 6 of his cards, Paul had four times as many cards as Dylan. How many cards did each of them have at first?
| |
Dylan |
Paul |
| Before |
1 u + 6 |
4 u - 39 |
| Change |
- 6 |
+ 39 |
| After |
1 u |
4 u |
Paul and Dylan had the same number of cards at first.
4 u - 39 = 1 u + 6
4 u - 1 u = 6 + 39
3 u = 45
1 u = 45 ÷ 3 = 15
Number of cards that each of them had at first
= 1 u + 6
= 15 + 6
= 21
Answer(s): 21
