Xavier and Simon had the same number of cards at first. After Xavier had bought another 26 cards and Simon had lost 10 of his cards, Xavier had thrice as many cards as Simon. How many cards did each of them have at first?
| |
Simon |
Xavier |
| Before |
1 u + 10 |
3 u - 26 |
| Change |
- 10 |
+ 26 |
| After |
1 u |
3 u |
Xavier and Simon had the same number of cards at first.
3 u - 26 = 1 u + 10
3 u - 1 u = 10 + 26
2 u = 36
1 u = 36 ÷ 2 = 18
Number of cards that each of them had at first
= 1 u + 10
= 18 + 10
= 28
Answer(s): 28
