David and Simon had the same number of cards at first. After David had bought another 40 cards and Simon had lost 8 of his cards, David had five times as many cards as Simon. How many cards did each of them have at first?
| |
Simon |
David |
| Before |
1 u + 8 |
5 u - 40 |
| Change |
- 8 |
+ 40 |
| After |
1 u |
5 u |
David and Simon had the same number of cards at first.
5 u - 40 = 1 u + 8
5 u - 1 u = 8 + 40
4 u = 48
1 u = 48 ÷ 4 = 12
Number of cards that each of them had at first
= 1 u + 8
= 12 + 8
= 20
Answer(s): 20
