Lee and Seth had the same number of cards at first. After Lee had bought another 36 cards and Seth had lost 10 of his cards, Lee had thrice as many cards as Seth. How many cards did each of them have at first?
| |
Seth |
Lee |
| Before |
1 u + 10 |
3 u - 36 |
| Change |
- 10 |
+ 36 |
| After |
1 u |
3 u |
Lee and Seth had the same number of cards at first.
3 u - 36 = 1 u + 10
3 u - 1 u = 10 + 36
2 u = 46
1 u = 46 ÷ 2 = 23
Number of cards that each of them had at first
= 1 u + 10
= 23 + 10
= 33
Answer(s): 33
