Pierre and Wesley had the same number of cards at first. After Pierre had bought another 39 cards and Wesley had lost 9 of his cards, Pierre had four times as many cards as Wesley. How many cards did each of them have at first?
| |
Wesley |
Pierre |
| Before |
1 u + 9 |
4 u - 39 |
| Change |
- 9 |
+ 39 |
| After |
1 u |
4 u |
Pierre and Wesley had the same number of cards at first.
4 u - 39 = 1 u + 9
4 u - 1 u = 9 + 39
3 u = 48
1 u = 48 ÷ 3 = 16
Number of cards that each of them had at first
= 1 u + 9
= 16 + 9
= 25
Answer(s): 25
