Sean and Brandon had the same number of cards at first. After Sean had bought another 30 cards and Brandon had lost 8 of his cards, Sean had thrice as many cards as Brandon. How many cards did each of them have at first?
| |
Brandon |
Sean |
| Before |
1 u + 8 |
3 u - 30 |
| Change |
- 8 |
+ 30 |
| After |
1 u |
3 u |
Sean and Brandon had the same number of cards at first.
3 u - 30 = 1 u + 8
3 u - 1 u = 8 + 30
2 u = 38
1 u = 38 ÷ 2 = 19
Number of cards that each of them had at first
= 1 u + 8
= 19 + 8
= 27
Answer(s): 27
