Lee and Sam had the same number of cards at first. After Lee had bought another 28 cards and Sam had lost 8 of his cards, Lee had thrice as many cards as Sam. How many cards did each of them have at first?
| |
Sam |
Lee |
| Before |
1 u + 8 |
3 u - 28 |
| Change |
- 8 |
+ 28 |
| After |
1 u |
3 u |
Lee and Sam had the same number of cards at first.
3 u - 28 = 1 u + 8
3 u - 1 u = 8 + 28
2 u = 36
1 u = 36 ÷ 2 = 18
Number of cards that each of them had at first
= 1 u + 8
= 18 + 8
= 26
Answer(s): 26
