Sean and George shared equally a bunch of lychees. After Sean had eaten 47 of his lychees and George had eaten 29 of his, George had 7 times as many lychees left as Sean. How many lychees had each of them at first?
| |
Sean |
George |
| Before |
1 u + 47 |
7 u + 29 |
| Change |
- 47 |
- 29 |
| After |
1 u |
7 u |
Number of lychees each had at first was the same.
7 u + 29 = 1 u + 47
7 u - 1 u = 47 - 29
6 u = 18
1 u = 18 ÷ 6 = 3
Number of lychees that they had each at first
= 1 u + 47
= 3 + 47
= 50
Answer(s): 50
