Justin and Ivan shared equally a bunch of longans. After Justin had eaten 32 of his longans and Ivan had eaten 16 of his, Ivan had 3 times as many longans left as Justin. How many longans had each of them at first?
| |
Justin |
Ivan |
| Before |
1 u + 32 |
3 u + 16 |
| Change |
- 32 |
- 16 |
| After |
1 u |
3 u |
Number of longans each had at first was the same.
3 u + 16 = 1 u + 32
3 u - 1 u = 32 - 16
2 u = 16
1 u = 16 ÷ 2 = 8
Number of longans that they had each at first
= 1 u + 32
= 8 + 32
= 40
Answer(s): 40
