Paul and Japheth shared equally a bunch of longans. After Paul had eaten 50 of his longans and Japheth had eaten 38 of his, Japheth had 3 times as many longans left as Paul. How many longans had each of them at first?
| |
Paul |
Japheth |
| Before |
1 u + 50 |
3 u + 38 |
| Change |
- 50 |
- 38 |
| After |
1 u |
3 u |
Number of longans each had at first was the same.
3 u + 38 = 1 u + 50
3 u - 1 u = 50 - 38
2 u = 12
1 u = 12 ÷ 2 = 6
Number of longans that they had each at first
= 1 u + 50
= 6 + 50
= 56
Answer(s): 56
