Cody and Glen shared equally a bunch of longans. After Cody had eaten 32 of his longans and Glen had eaten 20 of his, Glen had 4 times as many longans left as Cody. How many longans had each of them at first?
| |
Cody |
Glen |
| Before |
1 u + 32 |
4 u + 20 |
| Change |
- 32 |
- 20 |
| After |
1 u |
4 u |
Number of longans each had at first was the same.
4 u + 20 = 1 u + 32
4 u - 1 u = 32 - 20
3 u = 12
1 u = 12 ÷ 3 = 4
Number of longans that they had each at first
= 1 u + 32
= 4 + 32
= 36
Answer(s): 36
