Reggie and Tom shared equally a bunch of longans. After Reggie had eaten 39 of his longans and Tom had eaten 18 of his, Tom had 4 times as many longans left as Reggie. How many longans had each of them at first?
| |
Reggie |
Tom |
| Before |
1 u + 39 |
4 u + 18 |
| Change |
- 39 |
- 18 |
| After |
1 u |
4 u |
Number of longans each had at first was the same.
4 u + 18 = 1 u + 39
4 u - 1 u = 39 - 18
3 u = 21
1 u = 21 ÷ 3 = 7
Number of longans that they had each at first
= 1 u + 39
= 7 + 39
= 46
Answer(s): 46
