Pierre and Jack shared equally a bunch of longans. After Pierre had eaten 36 of his longans and Jack had eaten 24 of his, Jack had 4 times as many longans left as Pierre. How many longans had each of them at first?
| |
Pierre |
Jack |
| Before |
1 u + 36 |
4 u + 24 |
| Change |
- 36 |
- 24 |
| After |
1 u |
4 u |
Number of longans each had at first was the same.
4 u + 24 = 1 u + 36
4 u - 1 u = 36 - 24
3 u = 12
1 u = 12 ÷ 3 = 4
Number of longans that they had each at first
= 1 u + 36
= 4 + 36
= 40
Answer(s): 40
