Oliver and Owen shared equally a bunch of longans. After Oliver had eaten 47 of his longans and Owen had eaten 39 of his, Owen had 3 times as many longans left as Oliver. How many longans had each of them at first?
| |
Oliver |
Owen |
| Before |
1 u + 47 |
3 u + 39 |
| Change |
- 47 |
- 39 |
| After |
1 u |
3 u |
Number of longans each had at first was the same.
3 u + 39 = 1 u + 47
3 u - 1 u = 47 - 39
2 u = 8
1 u = 8 ÷ 2 = 4
Number of longans that they had each at first
= 1 u + 47
= 4 + 47
= 51
Answer(s): 51
