Lee and Dylan shared equally a bunch of rambutans. After Lee had eaten 48 of his rambutans and Dylan had eaten 27 of his, Dylan had 4 times as many rambutans left as Lee. How many rambutans had each of them at first?
| |
Lee |
Dylan |
| Before |
1 u + 48 |
4 u + 27 |
| Change |
- 48 |
- 27 |
| After |
1 u |
4 u |
Number of rambutans each had at first was the same.
4 u + 27 = 1 u + 48
4 u - 1 u = 48 - 27
3 u = 21
1 u = 21 ÷ 3 = 7
Number of rambutans that they had each at first
= 1 u + 48
= 7 + 48
= 55
Answer(s): 55
