Valen and Asher shared equally a bunch of longans. After Valen had eaten 30 of his longans and Asher had eaten 10 of his, Asher had 6 times as many longans left as Valen. How many longans had each of them at first?
| |
Valen |
Asher |
| Before |
1 u + 30 |
6 u + 10 |
| Change |
- 30 |
- 10 |
| After |
1 u |
6 u |
Number of longans each had at first was the same.
6 u + 10 = 1 u + 30
6 u - 1 u = 30 - 10
5 u = 20
1 u = 20 ÷ 5 = 4
Number of longans that they had each at first
= 1 u + 30
= 4 + 30
= 34
Answer(s): 34
