Lee and Andy shared equally a bunch of rambutans. After Lee had eaten 43 of his rambutans and Andy had eaten 31 of his, Andy had 5 times as many rambutans left as Lee. How many rambutans had each of them at first?
| |
Lee |
Andy |
| Before |
1 u + 43 |
5 u + 31 |
| Change |
- 43 |
- 31 |
| After |
1 u |
5 u |
Number of rambutans each had at first was the same.
5 u + 31 = 1 u + 43
5 u - 1 u = 43 - 31
4 u = 12
1 u = 12 ÷ 4 = 3
Number of rambutans that they had each at first
= 1 u + 43
= 3 + 43
= 46
Answer(s): 46
