Asher and Japheth shared equally a bunch of longans. After Asher had eaten 29 of his longans and Japheth had eaten 14 of his, Japheth had 6 times as many longans left as Asher. How many longans had each of them at first?
| |
Asher |
Japheth |
| Before |
1 u + 29 |
6 u + 14 |
| Change |
- 29 |
- 14 |
| After |
1 u |
6 u |
Number of longans each had at first was the same.
6 u + 14 = 1 u + 29
6 u - 1 u = 29 - 14
5 u = 15
1 u = 15 ÷ 5 = 3
Number of longans that they had each at first
= 1 u + 29
= 3 + 29
= 32
Answer(s): 32
