Ivan and Luke shared equally a bunch of grapes. After Ivan had eaten 46 of his grapes and Luke had eaten 22 of his, Luke had 4 times as many grapes left as Ivan. How many grapes had each of them at first?
| |
Ivan |
Luke |
| Before |
1 u + 46 |
4 u + 22 |
| Change |
- 46 |
- 22 |
| After |
1 u |
4 u |
Number of grapes each had at first was the same.
4 u + 22 = 1 u + 46
4 u - 1 u = 46 - 22
3 u = 24
1 u = 24 ÷ 3 = 8
Number of grapes that they had each at first
= 1 u + 46
= 8 + 46
= 54
Answer(s): 54
