Oliver and Harry shared equally a bunch of longans. After Oliver had eaten 26 of his longans and Harry had eaten 17 of his, Harry had 4 times as many longans left as Oliver. How many longans had each of them at first?
| |
Oliver |
Harry |
| Before |
1 u + 26 |
4 u + 17 |
| Change |
- 26 |
- 17 |
| After |
1 u |
4 u |
Number of longans each had at first was the same.
4 u + 17 = 1 u + 26
4 u - 1 u = 26 - 17
3 u = 9
1 u = 9 ÷ 3 = 3
Number of longans that they had each at first
= 1 u + 26
= 3 + 26
= 29
Answer(s): 29
