Fred and Cody shared equally a bunch of rambutans. After Fred had eaten 41 of his rambutans and Cody had eaten 15 of his, Cody had 3 times as many rambutans left as Fred. How many rambutans had each of them at first?
| |
Fred |
Cody |
| Before |
1 u + 41 |
3 u + 15 |
| Change |
- 41 |
- 15 |
| After |
1 u |
3 u |
Number of rambutans each had at first was the same.
3 u + 15 = 1 u + 41
3 u - 1 u = 41 - 15
2 u = 26
1 u = 26 ÷ 2 = 13
Number of rambutans that they had each at first
= 1 u + 41
= 13 + 41
= 54
Answer(s): 54
