George and Tom shared equally a bunch of grapes. After George had eaten 47 of his grapes and Tom had eaten 15 of his, Tom had 3 times as many grapes left as George. How many grapes had each of them at first?
| |
George |
Tom |
| Before |
1 u + 47 |
3 u + 15 |
| Change |
- 47 |
- 15 |
| After |
1 u |
3 u |
Number of grapes each had at first was the same.
3 u + 15 = 1 u + 47
3 u - 1 u = 47 - 15
2 u = 32
1 u = 32 ÷ 2 = 16
Number of grapes that they had each at first
= 1 u + 47
= 16 + 47
= 63
Answer(s): 63
