Zane and Flynn shared equally a bunch of longans. After Zane had eaten 49 of his longans and Flynn had eaten 33 of his, Flynn had 3 times as many longans left as Zane. How many longans had each of them at first?
| |
Zane |
Flynn |
| Before |
1 u + 49 |
3 u + 33 |
| Change |
- 49 |
- 33 |
| After |
1 u |
3 u |
Number of longans each had at first was the same.
3 u + 33 = 1 u + 49
3 u - 1 u = 49 - 33
2 u = 16
1 u = 16 ÷ 2 = 8
Number of longans that they had each at first
= 1 u + 49
= 8 + 49
= 57
Answer(s): 57
