Henry and George shared equally a bunch of rambutans. After Henry had eaten 37 of his rambutans and George had eaten 22 of his, George had 6 times as many rambutans left as Henry. How many rambutans had each of them at first?
| |
Henry |
George |
| Before |
1 u + 37 |
6 u + 22 |
| Change |
- 37 |
- 22 |
| After |
1 u |
6 u |
Number of rambutans each had at first was the same.
6 u + 22 = 1 u + 37
6 u - 1 u = 37 - 22
5 u = 15
1 u = 15 ÷ 5 = 3
Number of rambutans that they had each at first
= 1 u + 37
= 3 + 37
= 40
Answer(s): 40
