Riordan and Michael shared equally a bunch of longans. After Riordan had eaten 34 of his longans and Michael had eaten 19 of his, Michael had 4 times as many longans left as Riordan. How many longans had each of them at first?
| |
Riordan |
Michael |
| Before |
1 u + 34 |
4 u + 19 |
| Change |
- 34 |
- 19 |
| After |
1 u |
4 u |
Number of longans each had at first was the same.
4 u + 19 = 1 u + 34
4 u - 1 u = 34 - 19
3 u = 15
1 u = 15 ÷ 3 = 5
Number of longans that they had each at first
= 1 u + 34
= 5 + 34
= 39
Answer(s): 39
