Victoria had the same number of green, yellow and blue coins at first. After giving some green and yellow coins and 40 blue coins away, Victoria had 155 coins left. There were 2 times as many green coins as yellow coins left. The number of blue coins left was 15 fewer than the number of green coins left. How many blue coins did she have at first?
| |
Yellow |
Green |
Blue |
Total |
| Before |
2 u + 25 |
2 u + 25 |
2 u + 25 |
|
| Change |
- 1 u - 25 |
- 25 |
- 40 |
|
| After |
1 u |
2 u |
2 u - 15 |
155 |
Victoria had the same number of green, yellow and blue coins at first.
Total number of coins in the end
= 1 u + 2 u + 2 u - 15
= 5 u - 15
5 u - 15 = 155
5 u = 155 + 15
5 u = 170
1 u = 170 ÷ 5 = 34
Number of blue coins that Victoria had at first
= 2 u - 15 + 40
= 2 u + 25
= 2 x 34 + 25
= 93
Answer(s): 93
