Ivory had the same number of grey, yellow and red coins at first. After giving some grey and yellow coins and 50 red coins away, Ivory had 212 coins left. There were 3 times as many grey coins as yellow coins left. The number of red coins left was 12 fewer than the number of grey coins left. How many red coins did she have at first?
| |
Yellow |
Grey |
Red |
Total |
| Before |
3 u + 38 |
3 u + 38 |
3 u + 38 |
|
| Change |
- 2 u - 38 |
- 38 |
- 50 |
|
| After |
1 u |
3 u |
3 u - 12 |
212 |
Ivory had the same number of grey, yellow and red coins at first.
Total number of coins in the end
= 1 u + 3 u + 3 u - 12
= 7 u - 12
7 u - 12 = 212
7 u = 212 + 12
7 u = 224
1 u = 224 ÷ 7 = 32
Number of red coins that Ivory had at first
= 3 u - 12 + 50
= 3 u + 38
= 3 x 32 + 38
= 134
Answer(s): 134
