Nora had the same number of silver, green and black buttons at first. After giving some silver and green buttons and 74 black buttons away, Nora had 200 buttons left. There were 2 times as many silver buttons as green buttons left. The number of black buttons left was 30 fewer than the number of silver buttons left. How many black buttons did she have at first?
| |
Green |
Silver |
Black |
Total |
| Before |
2 u + 44 |
2 u + 44 |
2 u + 44 |
|
| Change |
- 1 u - 44 |
- 44 |
- 74 |
|
| After |
1 u |
2 u |
2 u - 30 |
200 |
Nora had the same number of silver, green and black buttons at first.
Total number of buttons in the end
= 1 u + 2 u + 2 u - 30
= 5 u - 30
5 u - 30 = 200
5 u = 200 + 30
5 u = 230
1 u = 230 ÷ 5 = 46
Number of black buttons that Nora had at first
= 2 u - 30 + 74
= 2 u + 44
= 2 x 46 + 44
= 136
Answer(s): 136
