Natalie had the same number of blue, black and yellow coins at first. After giving some blue and black coins and 41 yellow coins away, Natalie had 189 coins left. There were 2 times as many blue coins as black coins left. The number of yellow coins left was 11 fewer than the number of blue coins left. How many yellow coins did she have at first?
| |
Black |
Blue |
Yellow |
Total |
| Before |
2 u + 30 |
2 u + 30 |
2 u + 30 |
|
| Change |
- 1 u - 30 |
- 30 |
- 41 |
|
| After |
1 u |
2 u |
2 u - 11 |
189 |
Natalie had the same number of blue, black and yellow coins at first.
Total number of coins in the end
= 1 u + 2 u + 2 u - 11
= 5 u - 11
5 u - 11 = 189
5 u = 189 + 11
5 u = 200
1 u = 200 ÷ 5 = 40
Number of yellow coins that Natalie had at first
= 2 u - 11 + 41
= 2 u + 30
= 2 x 40 + 30
= 110
Answer(s): 110
