Nora had the same number of white, purple and gold coins at first. After giving some white and purple coins and 73 gold coins away, Nora had 205 coins left. There were 3 times as many white coins as purple coins left. The number of gold coins left was 26 fewer than the number of white coins left. How many gold coins did she have at first?
| |
Purple |
White |
Gold |
Total |
| Before |
3 u + 47 |
3 u + 47 |
3 u + 47 |
|
| Change |
- 2 u - 47 |
- 47 |
- 73 |
|
| After |
1 u |
3 u |
3 u - 26 |
205 |
Nora had the same number of white, purple and gold coins at first.
Total number of coins in the end
= 1 u + 3 u + 3 u - 26
= 7 u - 26
7 u - 26 = 205
7 u = 205 + 26
7 u = 231
1 u = 231 ÷ 7 = 33
Number of gold coins that Nora had at first
= 3 u - 26 + 73
= 3 u + 47
= 3 x 33 + 47
= 146
Answer(s): 146
