Marion had the same number of grey, yellow and gold buttons at first. After giving some grey and yellow buttons and 52 gold buttons away, Marion had 243 buttons left. There were 3 times as many grey buttons as yellow buttons left. The number of gold buttons left was 30 fewer than the number of grey buttons left. How many gold buttons did she have at first?
| |
Yellow |
Grey |
Gold |
Total |
| Before |
3 u + 22 |
3 u + 22 |
3 u + 22 |
|
| Change |
- 2 u - 22 |
- 22 |
- 52 |
|
| After |
1 u |
3 u |
3 u - 30 |
243 |
Marion had the same number of grey, yellow and gold buttons at first.
Total number of buttons in the end
= 1 u + 3 u + 3 u - 30
= 7 u - 30
7 u - 30 = 243
7 u = 243 + 30
7 u = 273
1 u = 273 ÷ 7 = 39
Number of gold buttons that Marion had at first
= 3 u - 30 + 52
= 3 u + 22
= 3 x 39 + 22
= 139
Answer(s): 139
