Yen had the same number of yellow, green and gold coins at first. After giving some yellow and green coins and 60 gold coins away, Yen had 169 coins left. There were 4 times as many yellow coins as green coins left. The number of gold coins left was 29 fewer than the number of yellow coins left. How many gold coins did she have at first?
| |
Green |
Yellow |
Gold |
Total |
| Before |
4 u + 31 |
4 u + 31 |
4 u + 31 |
|
| Change |
- 3 u - 31 |
- 31 |
- 60 |
|
| After |
1 u |
4 u |
4 u - 29 |
169 |
Yen had the same number of yellow, green and gold coins at first.
Total number of coins in the end
= 1 u + 4 u + 4 u - 29
= 9 u - 29
9 u - 29 = 169
9 u = 169 + 29
9 u = 198
1 u = 198 ÷ 9 = 22
Number of gold coins that Yen had at first
= 4 u - 29 + 60
= 4 u + 31
= 4 x 22 + 31
= 119
Answer(s): 119
