Olivia had the same number of black, green and silver coins at first. After giving some black and green coins and 73 silver coins away, Olivia had 158 coins left. There were 2 times as many black coins as green coins left. The number of silver coins left was 32 fewer than the number of black coins left. How many silver coins did she have at first?
| |
Green |
Black |
Silver |
Total |
| Before |
2 u + 41 |
2 u + 41 |
2 u + 41 |
|
| Change |
- 1 u - 41 |
- 41 |
- 73 |
|
| After |
1 u |
2 u |
2 u - 32 |
158 |
Olivia had the same number of black, green and silver coins at first.
Total number of coins in the end
= 1 u + 2 u + 2 u - 32
= 5 u - 32
5 u - 32 = 158
5 u = 158 + 32
5 u = 190
1 u = 190 ÷ 5 = 38
Number of silver coins that Olivia had at first
= 2 u - 32 + 73
= 2 u + 41
= 2 x 38 + 41
= 117
Answer(s): 117
