Xavier had $100 more than Lee. After each of them bought a different cardigan from a shop. Xavier and Lee were left with equal amount of money. Given that Xavier's cardigan cost 5 times as much as Lee's cardigan, how much did Xavier's cardigan cost?
|
Xavier |
Lee |
More |
Before |
1 u + 5 p |
1 u + 1 p |
$100 |
Change |
- 5 p |
- 1 p |
|
After |
1 u |
1 u |
|
The amount that Xavier and Lee had in the end is the same.
5 p - 1 p = 100
4 p = 100
1 p = 100 ÷ 4 = 25
Cost of Xavier's cardigan
= 5 p
= 5 x 25
= $125
Answer(s): $125