Ivory and Cindy had 860 coins altogether. They decided to play a game. In the first round, Cindy lost 52 coins to Ivory. In the second round, Ivory lost 35 coins to Cindy. At the end of the two rounds, Cindy had thrice as many coins as Ivory.
- How many coins did Ivory have in the end?
- How many coins did Cindy have at the beginning of the game?
|
Ivory |
Cindy |
Total |
Before |
1 u + 35 - 52 |
3 u - 35 + 52 |
860 |
Round 1 |
+ 52 |
- 52 |
|
Round 2 |
- 35 |
+ 35 |
|
After |
1 u |
3 u |
860 |
(a)
Total number of coins
= 1 u + 3 u
= 4 u
4 u = 860
1 u = 860 ÷ 4 = 215
Number of coins that Ivory had in the end
= 1 u
= 215
(b)
Working backwards.
Number of coins that Cindy had at the end of round 2
= 3 u
= 3 x 215
= 645
Number of coins that Cindy had at the end of round 1
= 645 - 35
= 610
Number of coins that Cindy had at the beginning of the game
= 610 + 52
= 662
Answer(s): (a) 215; (b) 662