Xylia and Kimberly had 900 stamps altogether. They decided to play a game. In the first round, Kimberly lost 59 stamps to Xylia. In the second round, Xylia lost 32 stamps to Kimberly. At the end of the two rounds, Kimberly had four times as many stamps as Xylia.
- How many stamps did Xylia have in the end?
- How many stamps did Kimberly have at the beginning of the game?
|
Xylia |
Kimberly |
Total |
Before |
1 u + 32 - 59 |
4 u - 32 + 59 |
900 |
Round 1 |
+ 59 |
- 59 |
|
Round 2 |
- 32 |
+ 32 |
|
After |
1 u |
4 u |
900 |
(a)
Total number of stamps
= 1 u + 4 u
= 5 u
5 u = 900
1 u = 900 ÷ 5 = 180
Number of stamps that Xylia had in the end
= 1 u
= 180
(b)
Working backwards.
Number of stamps that Kimberly had at the end of round 2
= 4 u
= 4 x 180
= 720
Number of stamps that Kimberly had at the end of round 1
= 720 - 32
= 688
Number of stamps that Kimberly had at the beginning of the game
= 688 + 59
= 747
Answer(s): (a) 180; (b) 747