Tammy and Xuan had 882 stamps altogether. They decided to play a game. In the first round, Xuan lost 58 stamps to Tammy. In the second round, Tammy lost 37 stamps to Xuan. At the end of the two rounds, Xuan had twice as many stamps as Tammy.
- How many stamps did Tammy have in the end?
- How many stamps did Xuan have at the beginning of the game?
|
Tammy |
Xuan |
Total |
Before |
1 u + 37 - 58 |
2 u - 37 + 58 |
882 |
Round 1 |
+ 58 |
- 58 |
|
Round 2 |
- 37 |
+ 37 |
|
After |
1 u |
2 u |
882 |
(a)
Total number of stamps
= 1 u + 2 u
= 3 u
3 u = 882
1 u = 882 ÷ 3 = 294
Number of stamps that Tammy had in the end
= 1 u
= 294
(b)
Working backwards.
Number of stamps that Xuan had at the end of round 2
= 2 u
= 2 x 294
= 588
Number of stamps that Xuan had at the end of round 1
= 588 - 37
= 551
Number of stamps that Xuan had at the beginning of the game
= 551 + 58
= 609
Answer(s): (a) 294; (b) 609