There are some buffaloes, ducks and sheep in a farm.There are 3 times as many ducks as sheep. Yen finds out that among the animals, there are a total of 32 heads and 98 legs. How many buffaloes are there?
Number of
4-legged animals |
Total legs of
4-legged animals |
Number of
2-legged animals |
Total legs of
2-legged animals |
Total legs |
32
|
32 x 4 =
128 |
0
|
0
|
128
|
31
|
31 x 4 =
124 |
1
|
1 x 2 =
2 |
126
|
17
|
17 x 4 =
68 |
15
|
15 x 2 =
30 |
30 |
Total number of legs if all are 4-legged animals
= 4 x 32
= 128
Big difference between all the 2-legged animals and all the 4-legged animals
= 128 - 98
= 30
Small difference between one 2-legged animal and one 4-legged animal
= 4 - 2
= 2
Number of ducks
= 30 ÷ 2
= 15
Number of 4-legged animals
= 32 - 15
= 17
Number of sheep = 1 u
Number of ducks = 3 u
3 u = 15
1 u = 15 ÷ 3 = 5
Number of sheep
= 1 u
= 5
Number of buffaloes
= 17 - 5
= 12
Answer(s): 12
