There are some buffaloes, chickens and pigs in a farm.There are 5 times as many chickens as pigs. Gem finds out that among the animals, there are a total of 38 heads and 92 legs. How many buffaloes are there?
Number of
4-legged animals |
Total legs of
4-legged animals |
Number of
2-legged animals |
Total legs of
2-legged animals |
Total legs |
38
|
38 x 4 =
152 |
0
|
0
|
152
|
37
|
37 x 4 =
148 |
1
|
1 x 2 =
2 |
150
|
8
|
8 x 4 =
32 |
30
|
30 x 2 =
60 |
60 |
Total number of legs if all are 4-legged animals
= 4 x 38
= 152
Big difference between all the 2-legged animals and all the 4-legged animals
= 152 - 92
= 60
Small difference between one 2-legged animal and one 4-legged animal
= 4 - 2
= 2
Number of chickens
= 60 ÷ 2
= 30
Number of 4-legged animals
= 38 - 30
= 8
Number of pigs = 1 u
Number of chickens = 5 u
5 u = 30
1 u = 30 ÷ 5 = 6
Number of pigs
= 1 u
= 6
Number of buffaloes
= 8 - 6
= 2
Answer(s): 2
