Liam had six times as much money as Howard. After Liam had spent $82, Howard had seven times as much money as Liam. How much more money than Howard had Liam at first?
| |
Liam |
Howard |
More |
Before
|
6x7 =
42 u |
1x7 =
7 u |
35 u |
| Change |
- $82 |
|
|
| After |
1 u |
7 u |
|
The amount that Howard had remains unchanged. Make the amount that Howard had the same. LCM of 1 and 7 is 7.
Amount that Mark had in the end = 1 u
42 u - 82 = 1 u
42 u - 1 u = 82
41 u = 82
1 u = 82 ÷ 41 = 2
Amount that Howard had more than Liam at first
= 42 u - 7 u
= 35 u
= 35 x 2
= $70
Answer(s): $70
