Howard had eight times as much money as Gabriel. After Howard had spent $71, Gabriel had nine times as much money as Howard. How much more money than Gabriel had Howard at first?
|
Howard |
Gabriel |
More |
Before
|
8x9 = 72 u |
1x9 = 9 u |
63 u |
Change |
- $71 |
|
|
After |
1 u |
9 u |
|
The amount that Gabriel had remains unchanged. Make the amount that Gabriel had the same. LCM of 1 and 9 is 9.
Amount that Mark had in the end = 1 u
72 u - 71 = 1 u
72 u - 1 u = 71
71 u = 71
1 u = 71 ÷ 71 = 1
Amount that Gabriel had more than Howard at first
= 72 u - 9 u
= 63 u
= 63 x 1
= $63
Answer(s): $63