Ahmad had six times as much money as Rael. After Ahmad had spent $99, Rael had twice as much money as Ahmad. How much more money than Rael had Ahmad at first?
| |
Ahmad |
Rael |
More |
Before
|
6x2 =
12 u |
1x2 =
2 u |
10 u |
| Change |
- $99 |
|
|
| After |
1 u |
2 u |
|
The amount that Rael had remains unchanged. Make the amount that Rael had the same. LCM of 1 and 2 is 2.
Amount that Mark had in the end = 1 u
12 u - 99 = 1 u
12 u - 1 u = 99
11 u = 99
1 u = 99 ÷ 11 = 9
Amount that Rael had more than Ahmad at first
= 12 u - 2 u
= 10 u
= 10 x 9
= $90
Answer(s): $90
