Ahmad had thrice as much money as Peter. After Ahmad had spent $65, Peter had twice as much money as Ahmad. How much more money than Peter had Ahmad at first?
| |
Ahmad |
Peter |
More |
Before
|
3x2 =
6 u |
1x2 =
2 u |
4 u |
| Change |
- $65 |
|
|
| After |
1 u |
2 u |
|
The amount that Peter had remains unchanged. Make the amount that Peter had the same. LCM of 1 and 2 is 2.
Amount that Mark had in the end = 1 u
6 u - 65 = 1 u
6 u - 1 u = 65
5 u = 65
1 u = 65 ÷ 5 = 13
Amount that Peter had more than Ahmad at first
= 6 u - 2 u
= 4 u
= 4 x 13
= $52
Answer(s): $52
