Tommy had thrice as much money as Dylan. After Tommy had spent $80, Dylan had twice as much money as Tommy. How much more money than Dylan had Tommy at first?
| |
Tommy |
Dylan |
More |
Before
|
3x2 =
6 u |
1x2 =
2 u |
4 u |
| Change |
- $80 |
|
|
| After |
1 u |
2 u |
|
The amount that Dylan had remains unchanged. Make the amount that Dylan had the same. LCM of 1 and 2 is 2.
Amount that Mark had in the end = 1 u
6 u - 80 = 1 u
6 u - 1 u = 80
5 u = 80
1 u = 80 ÷ 5 = 16
Amount that Dylan had more than Tommy at first
= 6 u - 2 u
= 4 u
= 4 x 16
= $64
Answer(s): $64
