Liam had four times as much money as Eric. After Liam had spent $77, Eric had twice as much money as Liam. How much more money than Eric had Liam at first?
| |
Liam |
Eric |
More |
Before
|
4x2 =
8 u |
1x2 =
2 u |
6 u |
| Change |
- $77 |
|
|
| After |
1 u |
2 u |
|
The amount that Eric had remains unchanged. Make the amount that Eric had the same. LCM of 1 and 2 is 2.
Amount that Mark had in the end = 1 u
8 u - 77 = 1 u
8 u - 1 u = 77
7 u = 77
1 u = 77 ÷ 7 = 11
Amount that Eric had more than Liam at first
= 8 u - 2 u
= 6 u
= 6 x 11
= $66
Answer(s): $66
