There were twice as many boys as girls at a conference. After 27 girls left the conference, there were five times as many boys as girls who remained behind. How many boys were there at the conference?
|
Boys |
Girls |
Before |
2x5 = 10 u |
1x5 = 5 u |
Change |
|
- 27 |
After |
5x2 = 10 u |
1x2 = 2 u |
The number of boys remained unchanged. Make the number of boys the same. LCM of 2 and 5 is 10.
Decrease in the number of girls
= 5 u - 2 u
= 3 u
3 u = 27
1 u = 27 ÷ 3 = 9
Number of boys
= 10 u
= 10 x 9
= 90
Answer(s): 90