There were thrice as many girls as boys at a celebration. After 12 boys left the celebration, there were five times as many girls as boys who remained behind. How many girls were there at the celebration?
|
Girls |
Boys |
Before |
3x5 = 15 u |
1x5 = 5 u |
Change |
|
- 12 |
After |
5x3 = 15 u |
1x3 = 3 u |
The number of girls remained unchanged. Make the number of girls the same. LCM of 3 and 5 is 15.
Decrease in the number of boys
= 5 u - 3 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Number of girls
= 15 u
= 15 x 6
= 90
Answer(s): 90