There were twice as many girls as boys at a celebration. After 12 boys left the celebration, there were five times as many girls as boys who remained behind. How many girls were there at the celebration?
|
Girls |
Boys |
Before |
2x5 = 10 u |
1x5 = 5 u |
Change |
|
- 12 |
After |
5x2 = 10 u |
1x2 = 2 u |
The number of girls remained unchanged. Make the number of girls the same. LCM of 2 and 5 is 10.
Decrease in the number of boys
= 5 u - 2 u
= 3 u
3 u = 12
1 u = 12 ÷ 3 = 4
Number of girls
= 10 u
= 10 x 4
= 40
Answer(s): 40