Valen had 218 more coins than Wesley at first. Then Valen bought 52 more coins. In the end, Valen has 4 times as many coins as Wesley.
- How many coins did Wesley have?
- Find the total number of coins Valen and Wesley had in the end?
| |
Valen |
Wesley |
Total |
| Before |
1 u + 218 |
1 u |
|
| Change |
+ 52 |
|
|
| After |
1 u + 218 + 52 |
1 u |
5 u |
(a)
Before
Number of coins that Valen had = 1 u + 218
Number of coins that Wesley had = 1 u
After
Number of coins that Valen had = 1 u + 218 + 52 = 4 u
Number of coins that Wesley had = 1 u
1 u + 218 + 52 = 4u
1 u + 270 = 4 u
4 u - 1 u = 270
3 u = 270
1 u = 270 ÷ 3 = 90
(a)
Number of coins that Wesley had
= 1 u
= 90
(b)
Number of coins that Valen and Wesley had in the end
= 4 u + 1 u
= 5 u
= 5 x 90
= 450
Answer(s): (a) 90; (b) 450
