Henry had 329 more coins than Gabriel at first. Then Henry bought 51 more coins. In the end, Henry has 3 times as many coins as Gabriel.
- How many coins did Gabriel have?
- Find the total number of coins Henry and Gabriel had in the end?
| |
Henry |
Gabriel |
Total |
| Before |
1 u + 329 |
1 u |
|
| Change |
+ 51 |
|
|
| After |
1 u + 329 + 51 |
1 u |
4 u |
(a)
Before
Number of coins that Henry had = 1 u + 329
Number of coins that Gabriel had = 1 u
After
Number of coins that Henry had = 1 u + 329 + 51 = 3 u
Number of coins that Gabriel had = 1 u
1 u + 329 + 51 = 3u
1 u + 380 = 3 u
3 u - 1 u = 380
2 u = 380
1 u = 380 ÷ 2 = 190
(a)
Number of coins that Gabriel had
= 1 u
= 190
(b)
Number of coins that Henry and Gabriel had in the end
= 3 u + 1 u
= 4 u
= 4 x 190
= 760
Answer(s): (a) 190; (b) 760
